What is the result of the expression `printf("%d", 5 + 2 * 3);` in C?

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In the expression printf("%d", 5 + 2 * 3);, the result is determined by the rules of operator precedence and associativity in C. The multiplication operator (*) has a higher precedence than the addition operator (+), which means that the multiplication will be performed first.

Breaking down the expression:

  1. The multiplication 2 * 3 is evaluated first, which equals 6.

  2. Then, the result of the multiplication is added to 5: 5 + 6, resulting in 11.

Thus, the value printed by the printf function will be 11. This demonstrates the importance of understanding operator precedence in expressions to correctly evaluate and predict the output of C code.

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